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rewona [7]
3 years ago
9

List five application programs you recommend, and write a sentence explaining why.

Computers and Technology
1 answer:
MArishka [77]3 years ago
5 0

Answer:

hi!

refer attachment

hope it helps!!?

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Assume that x is a char variable that has been declared and already given a value. Write an expression whose value is true if an
madam [21]
In Java, the character class has both an isDigit method and an isLetter method.

if (Character.isDigit(a) || Character.isLetter(a)){
return true;
} else {return fase;}
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How will computing change our world?
Eduardwww [97]
Well, currently in our revolving world, computers are mostly used which led to laziness for some people. However the school systems in most countries still depend on manual computing which can be really essential to the current generation. Computing can really change our current world, it helps us to not depend on computers, gives people more job opportunities. Helps to strengthen brain power which can contribute to large variety of factors. A smarter generation, and if possible, a more advance society.
7 0
3 years ago
Write a C function namedliquid()that is to accept an integer number and theaddresses of the variablesgallons,quarts,pints, andcu
salantis [7]

Answer:

#include <stdio.h>

#include <math.h>

void liquid(int ,int*,int*,int*,int*);

int main()

{

int num1, gallons, quarts, pints, cups;  

printf("Enter the number of cups:");

scanf("%2d",&num1);  

liquid(num1, &gallons, &quarts, &pints, &cups);  

return 0;

}  

void liquid(int x, int *gallons, int *quarts, int *pints, int *cups)

{

static int y;

y = x;  

if (y >= 16)

{

*gallons = (y / 16);

printf("The number of gallons is %3d\n", *gallons);

}

if (y - (*gallons * 16) >= 4)

{

*quarts = ((y - (*gallons * 16)) / 4);

printf("The number of quarts is %3d\n", *quarts);

}

if ((y - (*gallons * 16) - (*quarts * 4)) >= 2)

{

*pints = ((y - (*gallons * 16) - (*quarts * 4)) / 2);

printf("The number of pints is %3d\n", *pints);

}

if ((y - (*gallons * 16) - (*quarts * 4) - (*pints *2)) < 2 || y == 0)

{

*cups = (y - (*gallons * 16) - (*quarts * 4) - (*pints *2));

printf("The number of cups is %3d\n", *cups);

}

return;

}

5 0
3 years ago
Consider a network of 8 routers connected together to provide more than one path of connectivity between host A and host B at tw
ser-zykov [4K]

Answer:

Option C is the correct option to the following question

Explanation:

Because there are not any limits is required of sending data and packets between host A and host B by the routers and the router permit more than one paths between the hosts for the establishment of the connectivity st two distinct locations in the routing protocol. The router transmits the packets between the hosts that is produced by link-state protocol.

5 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
4 years ago
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