A little help?!
2 answers:
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Solution:
Total no. of incoming calls, n = 20
Probability of incoming calls with fax messages, p = 20% = 0.20
q = (1 - p) = 0.80
(a) Now, let 'r' be the no. of incoming calls with fax messages, then by Binomial distribution of probability mass function:
P(X = r) = (1)
P(X ≤ 7) =
P(X ≤ 7) = 0.0115 +........+ 0.0545
Total no. of incoming calls, n = 20
Probability of incoming calls with fax messages, p = 20% = 0.20
q = (1 - p) = 0.80
(a) Now, let 'r' be the no. of incoming calls with fax messages, then by Binomial distribution of probability mass function:
P(X = r) = (1)
P(X ≤ 7) =
P(X ≤ 7) = 0.0115 + 0.0545
P(X ≤ 7) = 0.9689
probability that atmost 7 of the calls are with fax is 0.9689