Well you can divide by 8 and it gives you 3/2or you can divide by 4 and get 6/4 then divide by 2 and get 3/2 either way there both correct
The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
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Well,
we know that we need to accumulate points from x and y to reach 20 points.
since x provide 3 and y provide 4 points, the formula would be :
3x + 4y = 20
or it can be written as :
y = (3x/4)+5
hope this helps
1)
n 1 2 3 4 5 6
f(n) 1033 932 831 730 629 528
First term (a₁): <u>1033 </u> Common difference (d): <u>-101 </u>
Explicit rule: 
Recursive rule: 
***********************************************************************************
2)
n 1 2 3 4 5 6
f(n) -39 -29 -19 -9 9 19
First term (a₁): <u> -39 </u> Common difference (d): <u> +10 </u>
Explicit rule: 
Recursive rule: 
***********************************************************************************
3)
n 1 2 3 4 5 6
f(n) 3.75 2.5 1.25 0 -1.25 -2.5
First term (a₁): <u> 3.75 </u> Common difference (d): <u> -1.25 </u>
Explicit rule: 
Recursive rule: 
