The probability that the teacher selects both boys from a seventh grader and eighth grader.
first calculate the probility that it is boy in each grade
7th
x = 7 / ( 7 + 3) = 7 / 10
8th
y = 2 / (2 + 2) = 1 / 2
so the probability
P = ( 7 / 10 ) ( 1 / 2 )
P = 0.35
Answer:
281 cups
Step-by-step explanation:
2000-1719= 281
Answer: Answer A 13
Step-by-step explanation: 20% of 65 is 13
Answer: The answer is -1.
Step-by-step explanation: Given that 'a' and 'b' are integers such that their product is 5. We are to find the least possible value of 'a to the power b'.
Since a and b are integers and a × b = 5, so their possible values are
For these only four choices of a and b, we have the following values of a to the power b:
since -1 is the smallest among these four values, so the least possible value of 'a to the power b' is -1.
Thus, the answer is -1.
Answer:
below
Step-by-step explanation:
You've been asked to use specific x-values. Simply replace the x in the equation for each of your x-values then graph.
first equation!!
(x,y)
y=-2x+5
x-value: -2
y=-2(-2)+5
y=4+5
y=9
(-2, 9)
x-value: -1
y=-2(-1)+5
y=2+5
y=7
(-1, 7)
x-value: 0
y=-2(0)+5
y=0+5
(0, 5)
x-value: 1
y=-2(1)+5
y=-2+5
y=3
(1, 3)
x-value: 2
y=-2(2)+5
y=-4+5
y=1
(2, 1)
second equation :)
(x,y)
y=x^2 +2
x-value: -2
y=-2^2 +2
y=4+2
y=6
(-2, 6)
x-value: -1
y=-1^2 +2
y=1+2
y=3
(-1, 3)
x-value: 0
y=0^2 +2
y=0+2
(0, 2)
x-value: 1
y=1^2 +2
y=1+2
y=3
(1, 3)
x-value: 2
y=2^2 +2
y=4+2
y=6
(2, 6)
third equation
(x,y)
y=√2 x+1
x-value: 1
y=√2 1+1
y=1+1
y=2
(1, 2)
x-value: 4
y=√2 4+1
y=2+1
y=3
(4, 3)
x-value: 9
y=√2 9+1
y=3+1
y=4
(9, 4)
x-value: 16
y=√2 16+1
y=4+1
y=5
(16, 5)
x-value: 25
y=√2 25+1
y=5+1
y=6
(25, 6)
fourth (last) equation :-)
(x,y)
y=4/x
x-value: -4
y=4/-4
y=-1
(-4, -1)
x-value: -2
y=4/-2
y=-2
(-2, -2)
x-value: -1
y=4/-1
y=-4
(-1, -4)
x-value: 0
y=4/0
y=0
(0, 0)
x-value: 1
y=4/1
y=4
(1, 4)
x-value: 2
y=4/2
y=2
(2, 2)
x-value: 4
y=4/4
y=1
(4, 1)