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3 years ago

A circle has a radius of 5 cm.

Mathematics

2 answers:

Stolb23 [73]3 years ago

7 0

Answer:

area = 78.540 cm ^2

Step-by-step explanation:

area = Pi (radius^2)

area = 3.14159(5^2) = 3.14159(25) = 78.5397

mina [271]3 years ago

4 0

Answer:

78.5

Step-by-step explanation:

pi r^2

22/7 * 5^2

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If 49x2 + 28x - 10 is rewritten as p2 + 4p -10, what is p in terms of p=

madam [21]

Answer:

p=7x

Step-by-step explanation:

49x^[2] + 28x - 10 = p^[2] + 4p -10

This equation is in the form a^[2]x + bx + c.

The 'c' is common for both equations, this means the 'a' and 'b' must also be common.

There are two ways to find p: 'a' or 'b'

a method

49x^[2] = p^[2]

=> The square root of both sides = 7x = p

b method

28x = 4p

28x/4 = 4p/4

7x = p

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3 years ago

Which shape is both rectangle and a square?

mina [271]

Step-by-step explanation:

the rhombus is both rectangle and square

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If a pound of apples cost $2.90 how much would 2.4 lbs cost

polet [3.4K]

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4 years ago

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Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago

-3×^5+11×^4+33×^3-26×^2 -36×-6/×^3+6×^2-3×-5 I keep getting this wrong

Andreas93 [3]

Answer:

$-3x^{2} + 29x - 150 + \frac{946x^{2} - 341x - 756}{x^{3} + 6x^{2} - 3x - 5}$

Step-by-step explanation:

There's a calculated explanation below. I hope this helps!

7 0

4 years ago