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tensa zangetsu [6.8K]
2 years ago
5

The ratio of girls to boys in a sports club is 3: 5

Mathematics
2 answers:
Semenov [28]2 years ago
6 0

Answer:

Their are 45 boys.

Step-by-step explanation:

Let's represent Girls by G,and Boys by B

so G = 27 and B = ? and G/B = 3:5 or 3/5

<u> </u><u>3</u><u> </u> = <u> </u><u>2</u><u>7</u><u> </u>

5. B

<u>3B</u> = <u>1</u><u>3</u><u>5</u>

3. 3

B = 45

natima [27]2 years ago
5 0

Answer:

45 boys

Step-by-step explanation:

The 3 part of the ratio refers to the number of girls.

Divide number of girls by 3 to find the value of one part of the ratio

27 ÷ 3 = 9 ← value of 1 part of the ratio, then

5 parts = 5 × 9 = 45 ← number of boys

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The mean weight of the domesticated house cat is 9.2 pounds with a standard deviation of 3.4 pounds. If a cat has a z-score of -
ra1l [238]

Answer:

4.78 pounds

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 9.2 pound

σ is the population standard deviation = 3.4 pounds

z = 1.3

We are to find x

Hence,

-1.3 = x - 9.2/3.4

Cross Multiply

-1.3 × 3.4 = x - 9.2

-4.42 = x - 9.2

x = -4.42 + 9.2

x = 4.78 pounds.

Therefore the weight of the cat is 4.78 pounds

5 0
3 years ago
Express 18 as a fraction of 27. <br> Give your answer in its simplest form
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Answer:

Thus, 2/3 is the simplified fraction for 18/27 by using the GCD or HCF method. Thus, 2/3 is the simplified fraction for 18/27 by using the prime factorization method

Step-by-step explanation:

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3 years ago
John spent half of his weekly allowance
Citrus2011 [14]

Answer:

$6

Step-by-step explanation:

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3 years ago
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2 years ago
An ornithologist has 4 bird feeders at separate locations. She wonders if birds are equally likely to visit each of the feeders.
Marianna [84]

Answer:

the x² test statistic 13.71

Option a) 13.71 is the correct answer.

Step-by-step explanation:

Given the data in the question;

Feeder                     1      2      3       4

Observed visits; o_i  60   90   92    58

data sample = 300

Expected e_i = 300 / 4 = 75

the x² test statistic = ?

X^2_{stat = ∑[ (o_i - e_i)²/e_i]

X^2_{stat = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]

X^2_{stat = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]

X^2_{stat = 13.7066 ≈ 13.71

Therefore, the x² test statistic 13.71

Option a) 13.71 is the correct answer.

7 0
2 years ago
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