Answer:
4.78 pounds
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 9.2 pound
σ is the population standard deviation = 3.4 pounds
z = 1.3
We are to find x
Hence,
-1.3 = x - 9.2/3.4
Cross Multiply
-1.3 × 3.4 = x - 9.2
-4.42 = x - 9.2
x = -4.42 + 9.2
x = 4.78 pounds.
Therefore the weight of the cat is 4.78 pounds
Answer:
Thus, 2/3 is the simplified fraction for 18/27 by using the GCD or HCF method. Thus, 2/3 is the simplified fraction for 18/27 by using the prime factorization method
Step-by-step explanation:
hope l am not late!
Answer:
$6
Step-by-step explanation:
The picture isn’t loading can you re do it because I don’t see it????
Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits; 
60 90 92 58
data sample = 300
Expected 
= 300 / 4 = 75
the x² test statistic = ?
= ∑[ ( - )²/]
= [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
= [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
= 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.
