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3 years ago

Please answer this question thank you.

Mathematics

2 answers:

finlep [7]3 years ago

8 0

1450 divided by 29.6 equals 48.9 move the decimal to the left and you get c

Nezavi [6.7K]3 years ago

7 0

Answer:

Option B is correct, mark me brainliest please

Step-by-step explanation:

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The area of a square is defined by, A(x) = x 2 - 6x + 9. What is the length of a side of the square?

Dmitriy789 [7]

A9x) = x^2 - 6x + 9 = (x - 3)^2

length of a side = x - 3

8 0

3 years ago

What is 8^2 + 15^2= c^2

Tasya [4]

Answer:

$8^2\:+\:15^2=\:c^2$

c = 17

Step-by-step explanation:

This is the Pythagorean theorem

6 0

3 years ago

Read 2 more answers

If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3

horrorfan [7]

Answer: The correct option is (B) 24 : 25.

Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

$\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Therefore, the ratio of the area of R to the area of S is

$\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.$

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0

4 years ago

A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s

belka [17]

Answer:

k = $\frac{980a}{b}$

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

= 9.8a

Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = $\frac{9.8a}{0.01b}$

k = $\frac{980a}{b}$

Therefore, spring constant of the spring will be determined by the expression, k = $\frac{980a}{b}$

4 0

3 years ago

For his book report, Bobby made color copies and black-and-white copies. The black-and-white copies cost $2.75 in all. The color

Feliz [49]

16, i think it is the right answer.

3 0

3 years ago