A. If you use only the coupon you will have to pay $137.50.
B. Using the Coupon during the sale, the kit is discounted by $112.50
C. The total percent discount is 45% after both discounts.
Step-by-step explanation:
Step 1; The store has the robotics kit for a sale of 25% off $250. So we need to find how much 25% is in terms of $250. To do that we convert 25% into a fraction by dividing it by 100 and multiplying it with $250.
25% of $250 =
× $250 = 0.25 × $250 = $62.50
So we find the cost of the kit due to the store's discount. To do that we subtract the discounted price from the original price.
Robotics kit price after 25% discount = $250 - $62.50 = $187.50.
Step 2; A coupon you have gives you an additional 20% discount. So the robotics kit can be brought for 25% off due to the sale at the store, due to this coupon you get an additional 20%. So you get a 45% discount off $250.
45% of $250 =
× $250 = 0.45 × $250 = $112.50.
So to find the total discount we subtract this $112.50 from the non-discounted cost of $250.
Total discounted price = $250 - $112.50 = $137.50.
Answer:
π/6 [37^(³/₂) − 1] ≈ 117.3187
Step-by-step explanation:
The surface area is:
S = ∫ 2π (x − 0) √(1 + (dx/dy)²) dy
0 ≤ x ≤ 3, so -4 ≤ y ≤ 5.
Find dx/dy.
y = 5 − x²
x² = 5 − y
x = √(5 − y)
dx/dy = ½ (5 − y)^(-½) (-1)
dx/dy = -½ (5 − y)^(-½)
(dx/dy)² = ¼ (5 − y)^(-1)
(dx/dy)² = 1 / (4 (5 − y))
Plug in:
S = ∫₋₄⁵ 2π x √(1 + 1 / (20 − 4y)) dy
S = ∫₋₄⁵ 2π √(5 − y) √(1 + 1 / (4 (5 − y))) dy
S = ∫₋₄⁵ 2π √((5 − y) + 1/4)) dy
S = ∫₋₄⁵ 2π √(5.25 − y) dy
If u = 5.25 − y, then du = -dy.
S = ∫ 2π √u (-du)
S = -2π ∫ √u du
S = -2π (⅔ u^(³/₂))
S = -4π/3 u^(³/₂)
Substitute back:
S = -4π/3 (5.25 − y)^(³/₂)
Evaluate between y=-4 and y=5.
S = [-4π/3 (5.25 − 5)^(³/₂)] − [-4π/3 (5.25 − -4)^(³/₂)]
S = -4π/3 (0.25)^(³/₂) + 4π/3 (9.25)^(³/₂)
S = π/6 [37^(³/₂) − 1]
S ≈ 117.3187
Add the total of tosses: (18 + 12 = 30)
divide experimental heads by total tosses
12/30 = 2/5
as a decimal is 0.4