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Evgesh-ka [11]
3 years ago
5

Please marking brainlist 3+9y+2=

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

It’s 14 due to the formules used

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HELPP!!! 15 PPP ill mark you as brain!
vesna_86 [32]

Alright so first he paid 45 for the guitar he resold it for 51.75(15% of 45 is 6.75) then spent 18.63(36% is 18.63)on books

I hope this helped...

3 0
4 years ago
I need the answer and the answers are there
sergeinik [125]

Answer:

Step-by-step explanation:

5 0
3 years ago
Determine the wavelengths of all the possible photons that can be emitted from the n = 5 state of a hydrogen atom.
KonstantinChe [14]

Answer:

Wavelengths of all possible photons are;

λ1 = 9.492 × 10^(-8) m

λ2 = 1.28 × 10^(-6) m

λ3 = 1.28 × 10^(-6) m

λ4 = 4.04 × 10^(-6) m

Step-by-step explanation:

We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.

It's given by;

1/λ = R(1/(n_f)² - 1/(n_i)²)

Where;

λ is wavelength

R is Rydberg's constant = 1.0974 × 10^(7) /m

n_f is the final energy level = 1,2,3,4

n_i is the initial energy level = 5

At n_f = 1,.we have;

1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)

1/λ = 10535040

λ = 1/10535040

λ = 9.492 × 10^(-8) m

At n_f = 2,.we have;

1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.21)

1/λ = 2304540

λ = 1/2304540

λ = 4.34 × 10^(-7) m

At n_f = 3, we have;

1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.07111)

1/λ = 780373.3333333334

λ = 1/780373.3333333334

λ = 1.28 × 10^(-6) m

At n_f = 4, we have;

1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.0225)

1/λ = 246915

λ = 1/246915

λ = 4.04 × 10^(-6) m

5 0
3 years ago
What is 145/8 as a decimal numbers
Makovka662 [10]
The answer is 18.13

(145/8) ÷ 2 » 18.125 ÷ 2 = 9.0625 is how I get this answer
6 0
3 years ago
It is important to remember that random coincidences are truly random and _____ correlated
SIZIF [17.4K]
Random coincidences are set of coincidences which have been selected randomly and thus they don't posses any particular relationship at all. This means that they do not have any dependencies whatsoever and thus, the relationship of random event A to random event say B or C or D is purely none. Therefore, whenever A occurs B will not be affected and whenever B or C or D occurs, A will not be affected at all. Therefore random coincidences are truly random and NOT correlated.
4 0
4 years ago
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