Answer:
In a function prototype the heading is followed by a semicolon, whereas in a function definition the heading is followed by a function block.
Explanation:
As the function prototype only declares the function and the function definition defines the operations in the function.
e.g:
add(int x, int y); is the prototype
add(int x, int y)
{
int sum;
sum x
y;
} is the function definition.
The program calculates the velocity between points in a list is written below. The program is written in python 3 thus ;
t = input("Enter time values : ")
<em>#Enter</em><em> </em><em>the</em><em> </em><em>time</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>data</em>
p = input("Enter distance values : ")
<em>#Enter</em><em> </em><em>the</em><em> </em><em>distance</em><em> </em><em>values</em>
dist = [float(x) for x in p.split()]
time = [float(x) for x in t.split()]
<em>#pyt</em><em> </em><em>then</em><em> </em><em>values</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>list</em><em> </em>
def partfthat(dist, time):
<em>#initialize</em><em> </em><em>function</em><em> </em><em>that</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>
vel = []
<em>#empty</em><em> </em><em>list</em><em> </em><em>to</em><em> </em><em>hold</em><em> </em><em>the</em><em> </em><em>calculated</em><em> </em><em>velocity</em><em> </em><em>values</em><em> </em>
i = 0
<em>#indexer</em><em> </em>
while i <= len(dist)-2:
<em>#while</em><em> </em><em>loop</em><em> </em><em>to</em><em> </em><em>iterate</em><em> </em>
v = (dist[i+1] - dist[i]) / (time[i+1] -time[i])
<em>#</em><em>Use</em><em> </em><em>the</em><em> </em><em>velocity</em><em> </em><em>formula</em><em> </em>
vel.append(v)
<em>#append</em><em> </em><em>values</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>empty list</em><em> </em><em>created</em><em> </em>
i+=1
return vel
print(avg_vel(dist, time))
<em>A</em><em> </em><em>sample</em><em> </em><em>run</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>program</em><em> </em><em>is</em><em> </em><em>attached</em><em>.</em><em> </em>
Learn more : brainly.com/question/25681441
Answer:
I am writing a C++ and JAVA program.
import java.util.Scanner; //for using input output functions
public class LabProgram { // class name
public static void main(String[] args) {//start of main function body
Scanner input = new Scanner(System.in);
// creates input instance of Scanner type
String str; // declares String type variable str for a string value
int num; // declares integer type variable num to hold an integer value
str = input.next(); //scans and reads input string from user
num = input.nextInt(); //scans and reads input integer from user
//while loop continues to execute until user enters quit 0
while(str!="quit" && num!=0) {
/* prints the following message, for example if value of num = 2 and value of str = apples then the following print statement prints Eating 2 apples a day keeps the doctor away. */
System.out.println("\nEating " + num +" " + str + " a day keeps the doctor away.");
//takes string and integer as input again and keep taking input until user //enters quit 0
str = input.next();
num = input.nextInt(); } } }
Explanation:
The program is well explained in the comments mentioned with each statement of the program. The program simply prompts user to enter a string and an integer. The while loop keeps executing until user enters quit 0. The program keeps taking input string and integer from user and prints the message System.out.println("\nEating " + num +" " + str + " a day keeps the doctor away."); The loop breaks when the use enters quit 0. The screenshot of the program along with its output is attached.
