The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Im mot sure of the answer
You need to use the identity
cos(90-u)=sin(u)
if u=x-20
cos(90-x+20)=sin(x-20)
cos(110-x)=sin(x-20)
substituting in the original function
cos(110-x)=cos(42)
for the functions to be equal there input must be equal
110-x=42
x=68