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2 years ago

10

Help me please its due in 30 minutes!

2 answers:

miss Akunina [59]2 years ago

5 0

Answer:

angle KMI = 136°

I hope this may be helpful

juin [17]2 years ago

5 0

Answer:

pretty sure the answer is a

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

you run 10 miles in 1 hour and 15 mintues keeping the same pance how long would it take to run 15miles

Montano1993 [528]

Answer:

1 hour and 30 minutes

Step-by-step explanation:

because it took an hour for 10 mile so add another five miles and it would take 30 minutes

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME (URGENT)!!!!!<br>EXTRA POINTS WILL BE GIVEN TO THE BRAINLIEST ANSWER!!!

kolbaska11 [484]

Answer:

Square. If the middle is 90° then all of them have to be.

5 0

3 years ago

Read 2 more answers

Please i need ur help <3

deff fn [24]

Hello!! the answer is 3xy

8 0

2 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

so

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

2 years ago