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dexar [7]
3 years ago
12

What is two and one third times four fifths

Mathematics
2 answers:
Alik [6]3 years ago
6 0

Answer:

2.26666667

Step-by-step explanation:

Stay Frosty

MaRussiya [10]3 years ago
5 0

Answer:

28/15

Step-by-step explanation:

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Write each fraction in simplest form 18 divided by 9
defon

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The current temperature in Smalltown is 20 degrees. This is 6 degrees less than twice the temperature(t) that it was six hours a
tia_tia [17]
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6 0
3 years ago
Simplify this equation <br> Thanks a lot!!!
den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

4 0
3 years ago
Function c
r-ruslan [8.4K]
Give me brainliest becuase 2+2=4 isn’t that enough help?
6 0
3 years ago
(2, 7) and (-6, -2) find the distance between each pair of points
yaroslaw [1]

Answer:

\sqrt{145}

Step-by-step explanation:

Hi there!

We are given the points (2, 7) and (-6, -2). We want to find the distance between them. To do that, we can use the distance formula

The distance formula is given as \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are points

We have 2 points, which is what we need to find the distance, but let's label their values to avoid any confusion

x_1=2\\y_1=7\\x_2=-6\\y_2=-2

Now substitute those values into the formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\sqrt{(-6-2)^2+(-2-7)^2}

Simplify the values under the radical:

\sqrt{(-8)^2+(-9)^2}

Raise to the second power:

\sqrt{64+81}

Add the numbers under the radical together

\sqrt{145}

The answer can be left as that, as the radical cannot be simplified.

Hope this helps!

7 0
3 years ago
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