86 *2 = 172
172/3 = 57.33
54 + 56 +58 =168
168/2 =84
56 + 58 +60 = 174
174/2 =87
58 +60 +62 = 180
180/2 = 90
60 +62 +64 = 186
186/2 = 93
62 +64+66 = 192
192/2 = 96
there are 3 sets of numbers that fall between 84 & 96
1 set equals 84 and 1 set equals 96
so if you are counting those there are 5 sets
Following rules of logs, we can do the following:
log x^4 - log y^(1/2) + log z^3
Combine the first and 3rd factors to get log [x^4*z^3]
Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:
[x^4*z^3]
log ----------------
y^(1/2)
Next time, please include the instructions when you present your problem.
Thx.
<span>
C.
His college savings account has a balance of $13,700.</span>
Answer:
y>3
Step-by-step explanation:
9>-3y
3<y
y>3