Answer:
x=3
Step-by-step explanation:
x^2 = 6x - 9
Subtract 6x from each side
x^2 -6x = -9
Add 9 to each side
x^2 -6x+9 = 0
Factor
what 2 numbers multiply to 9 and add to -6
-3*-3 = 9
-3+-3 =-6
(x-3)(x-3) = 0
Using the zero product property
x-3 =0 x-3=0
x=3 with multiplicity 2
The Equation is y=+5
Why:
You want to find the equation for a line that passes through the point (-4,5) and has a slope of .
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was . So you can right away fill in the equation for a line somewhat to read:
y=x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-4,5). When x of the line is -4, y of the line must be 5.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-4,5).
So, why not plug in for x the number -4 and for y the number 5? This will allow us to solve for b for the particular line that passes through the point you gave!.
(-4,5). y=mx+b or 5=0 × -4+b, or solving for b: b=5-(0)(-4). b=5.
The range would be 0, -3, -9, 5, and 7. The range includes all y values or output values.
Answer: The answer is D
Step-by-step explanation:
I used desmos graphing calculator! Look it up it really helps! Literally gives the answers. :)
