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Taya2010 [7]
3 years ago
10

HELLLLLLLPPPPPPPPPP MEEEEEEEEEEEEEEEEEEE

Mathematics
2 answers:
Mariana [72]3 years ago
7 0

I think the answer might be $9

Blababa [14]3 years ago
4 0

Answer: it will cost abt $13 to make 50 cups but the best one bellow would be $9

Step-by-step explanation:

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How to model the problem
Ilia_Sergeevich [38]
Change 5/3 to 15/9. Then add 15 + 17 and put it over 9. 32/9
7 0
3 years ago
What is the answer for this problem
Tasya [4]

Answer: Y= -3/7+5

Step-by-step explanation:

4 0
2 years ago
One-third of a number t is less than or equal to 5
Kryger [21]

Answer:

t ≤ 15

Step-by-step explanation:

One third of 15 is equal to five (1/3 × 15 = 5)

One third of t is lesser than or equal to five (1/3 × 5 ≤ 5)

<em>So, t cannot be more than 15.</em><em> </em><em>It</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>1</em><em>5</em><em>,</em><em> </em><em>though</em><em>.</em>

∴t ≤ 15

7 0
3 years ago
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
Prove that they are equal
Westkost [7]

Step-by-step explanation:

(1-tanx)/(1+tanx) = (1-sin2x)/cos2x

Replace tanx with sinx/cosx:

(1-sinx/cosx)/(1+sinx/cosx)

Multiply numerator and denominator by cosx:

(cosx-sinx)/(cosx+sinx)

Multiply numerator and denominator by cosx-sinx:

(cos^2x-2sinxcosx+sin^2x)/(cos^2x-sin^2x)

For the numerator, since sin2x = 2sinxcosx, and sin^2x + cos^2x = 1, we have 1-sin2x

For the denominator, cos^2x - sin^2x = cos2x

So (1-tanx)/(1+tanx) = (1-sin2x)/cos2x

4 0
4 years ago
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