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3 years ago

URGENT.!! NEED HELP ASAP.!!! 50 PONTS.!!!!!!!!

Mathematics

2 answers:

Katen [24]3 years ago

7 0

Answer:

y= 4x-4

y= x +2

Step-by-step explanation:

BartSMP [9]3 years ago

6 0

The last one is y= 4x-4
The second one is y= x +2
The first one is y= -x + 2

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A number decreased by 5 is 50

Vinil7 [7]

Answer:

55 decrease by 5 is 50, or 55 - 5 = 50.

Step-by-step explanation:

Let x represent the missing number.

When you hear the words decrease, minus, that tells you to subtract.

Before we subtract, if there is a variable, we must do the opposite of subtraction, we need to add.

50 + 5 = x

Which means x = 50 + 5.

50 + 5 = 55.

Therefore, x = 55.

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3 years ago

Adele opens an account with $100 and deposits $45 a month. Kent opens an account with $70 and also deposits $45 a month. Will th

Harman [31]

answer:

Adele and Kent will not have the same amount in their account at the same time. because they both are going at the same rate depositing 45$a month Adele is ahead by 30$ because she deposited 100 instead of 70 in the beginning. They will be at the same point if Kent deposits more or Adele deposit less.

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3 years ago

Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected

baherus [9]

Wow collage seems so hard

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3 years ago

The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q

Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

$\frac{\sum f}{4}=\frac{100}{4}=25$

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF) $_{p}$ = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

$=34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75$

The value of first quartile is 34.75.

Q₃ is at the position:

$\frac{3\sum f}{4}=\frac{3\times100}{4}=75$

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF) $_{p}$ = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

$=44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83$

The value of third quartile is 44.83.

Then the inter-quartile range is:

$IQR = Q_{3}-Q_{1}$

$=44.83-34.75\\=10.08$

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

$P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}$

$=\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89$

Thus, the probability that a student scored at most 50 on the examination is 0.89.

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4 years ago

A manufacturing unit currently operates at 80 percent of its capacity. The profit function for the unit at the optimum output, x

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B.
I hope I helped!!!!!!!!!

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3 years ago

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