Answer:
5.36 moles
Explanation:
From the given chemical equation, we see that one mole of nitrogen gas reacts with 3 moles of hydrogen gas in terms of mass.
Molar mass of hydrogen gas ; H2 = 2.016 g/mol
Molar mass of nitrogen gas; N2 = 28.01 g/mol
Thus;
28.01 grams of nitrogen gas requires 3 moles of hydrogen gas
Thus;
28.01 grams of nitrogen gas requires 3 moles of hydrogen gas
Therefore, 50 g of nitrogen gas will require; (50 × 3)/28.01 = 5.36 moles
Answer: In ionic bonding (a noble gas configuration is formed for each element or ion).
Explanation:
IONIC bonding, which is also called electrovalent bonding involves the complete transfer of electrons from one atom to another in order to attain a noble gas electron configuration.
The noble gases or group 0 elements have a completely filled outermost shell of eight electrons. This makes them generally very stable, that is, unreactive. There is a natural drive for other atoms to attain the electron configuration of group 0 (inert gases) elements. This usually results in atoms entering into chemical combinations by losing, gaining or sharing electrons.
Ionia compound such as sodium chloride
--> have high melting points because alot of heat energy is required to break the attractive forces between the ions;
--> are hard and brittle;
--> are soluble in water;
--> conduct electricity when in solution or molten form because the ions are able to move about, that is, they are electrolytes
If we draw the lewis structure, we can see that all Cl
atoms are all connected to the B atom. Now Cl atoms has 7 electrons each on its
outermost shell while B can donate 3 electrons. So by octet rule, each Cl will
gain 1 electron each from the B atom. From the Lewis structure, we can see that
there are actually No Lone pairs on the central atom.
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Answer:
Energy
Explanation:
Air water and the sun form energy. Unless your talking about evaporation, which water gets heated from the sun which turns into air (water vapor)
M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol
m(N)=M(N)m(KNO₃)/M(KNO₃)
m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)
2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)
m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))
m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g