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7nadin3 [17]
3 years ago
11

HELP ME WALLAHO HELP ME WALLAHI HELP

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

13

Step-by-step explanation:

Draw a picture!

You have a right triangle with legs of 5 and 12.

By the Pythagorean Theorem, the hypotenuse is √(5²+12²) = 13

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Find the zero of f (x-5) (-x to the second power +3x-3)
FromTheMoon [43]

Answer:

1 =x-5 = as pytanerosa tery says

23

Step-by-step explanation:

6 0
2 years ago
What is the equation for the line? enter your answer in the box
Igoryamba
To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)

The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept

First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c

Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4

Based on the above calculations, the equation of the line is:
y = -2x - 4
7 0
2 years ago
For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
Rus_ich [418]

To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

x\frac{3}{2} is the required solution of the given inequality.

5 0
3 years ago
Read 2 more answers
Which of the following is a postulate or theorem used to prove two triangles are congruent?
nydimaria [60]
I think it's SSS or SAS
5 0
3 years ago
Who knows this answer
artcher [175]

Answer: A is correct answer

Step-by-step explanation:

8 0
2 years ago
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