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CaHeK987 [17]
3 years ago
13

What is the image point of (2,0) after the transformation rx-axis o T1,-1?

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0

Answer:

-2,0

Step-by-step explanation:

WITCHER [35]3 years ago
5 0

Answer:3,1

Step-by-step explanation:

You might be interested in
Question 13 I don’t know how to do it
Gekata [30.6K]

Answer:

y = - \frac{1}{4} (x - 1)²(x + 2)(x + 6)

Step-by-step explanation:

The roots from the graph are

x = - 6 , then factor is (x + 6)

x = - 2 , then factor is (x + 2)

x = 1 ( multiplicity 2 ) , then factor is (x - 1)² then

y = a(x - 1)²(x + 2)(x + 6) ← a is a multiplier

To find a substitute any point on the graph into the equation

Using (0, - 3 ), then

- 3 = a(- 1)²(2)(6) = 12a ( divide both sides by 12 )

- \frac{1}{4} = a

Then

y = - \frac{1}{4} (x - 1)²(x + 2)(x + 6)

8 0
3 years ago
Which ordered pair is a solution to the system of inequalities graphed here?
Ghella [55]

<em>The origin (0, 0) is a solution to this system.</em>

<h2>Explanation:</h2>

Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any system of inequalities, so I'll give you this system:

\left\{ \begin{array}{c}y\ge x-5\\y\le2x+3\end{array}\right.

For the first inequality, the shaded region is above the line y=x-5 and every point on the line is included in its solution since equality is included in ≥, so the line is dashed. On the other hand, for the second inequality the shaded region is below the line y=2x+3 and every point on this line is not included in the solution since equality is not included in <, so the line is dotted.

Finally, the solution to this system of inequalities is the intersection of both regions as indicated in the graph below.

As you can see, the origin (0, 0) is a solution to this system.

<h2>Learn more:</h2>

Inequalities: brainly.com/question/13177145

#LearnWithBrainly

5 0
4 years ago
How do you solve this?
Katyanochek1 [597]
Use pythagoras theorem because there’s a right angled triangle
5 0
4 years ago
ABCD and EFGH are squares. If JH= 4cm and JC=9cm, then what is the area of the shaded region?
romanna [79]
The squares are shown in the attached picture.

As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.

In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).

The area of a square know the diagonal is given by the formula:
A = d² ÷ 2

A(ABCD) = (2×JC)² ÷ 2
                = (2×9)² ÷ 2
                = 162 cm²

A(EFGH) = (2×JH)² ÷ 2
               = (2×4)² ÷ 2
               = 32 cm²

Therefore:
A = A(ABCD) - <span>A(EFGH)
   = 162 - 32
   = 130 cm</span>²

The area of the shaded region is 130 cm².

3 0
3 years ago
Solve this problem pls ​
lina2011 [118]

Answer:

1) 200.

Step-by-step explanation:

Men = 1/³

Women = ⅔

50 men, 100 women

2:1 women to men.

there are 200 people in total.

5 0
2 years ago
Read 2 more answers
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