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poizon [28]
3 years ago
9

How to find leg length of isosceles triangle using base angles?

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0
Take the perimiter, subtract the bottom and divide by two
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Find the measure of angle x. Round your answer to the nearest hundredth. (please type the numerical answer only) (6 points)
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Answer:

Step-by-step explanation:

sin(x°) = 4/5

x° = arcsin(4/5) ≅ 53.1°

3 0
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5 0
3 years ago
If f(x)= x/3-2then find g(x) =3x^2+2x-6
Alexxx [7]

Answer:

Step-by-step explanation:

Answer:

(f+g)(x)=3x^2+\frac{7}{3}x-8  

Step-by-step explanation:

The given functions are:

f(x)=\frac{x}{3}-2 and g(x)=3x^2+2x-6

Now, (f+g)(x)=f(x)+g(x)

therefore, (f+g)(x)=\frac{x}{3}-2+3x^2+2x-6

=3x^2+2x+\frac{x}{3}-8

=\frac{9x^2+6x+x-24}{3}

=\frac{9x^2+7x-24}{3}

=3x^2+\frac{7}{3}x-8

Thus, (f+g)(x)=3x^2+\frac{7}{3}x-8

6 0
3 years ago
Please help me with this question. Thanks
Oksana_A [137]

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a) no

b) yes

c) no

d) yes

please mark as brainlist

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