Answer:
The time the two planes will meet is 1.43 hours
Step-by-step explanation:
Given;
speed of the first plane in positive direction, = 40 mph
speed of the second plane in negative direction(opposite direction) = -100 mph
distance between the two planes = 200 miles
Let the time the two planes will meet = t
the position of the first plane at this time "t" = 40t
the position of the second plane at this time "t" = -100t
(40t)>--------------------------------<(-100t), this space between them is 200 miles.
Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.
40t - (-100t) = 200
40t + 100t = 200
140t = 200
t = 200 / 140
t = 1.43 hours
Therefore, the time the two planes will meet is 1.43 hours
One side is 9.
second side (3x+1) is 28.
third side (4x-9) is 27.
Answer:
b
Step-by-step explanation:
