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anyanavicka [17]
3 years ago
8

What is the purpose of taking a personality inventory assessment?

SAT
1 answer:
ValentinkaMS [17]3 years ago
8 0
I’m pretty sure it’s A
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Use the sample data and confidence level given below to complete parts a through d.
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Using the information given and the z-distribution, it is found that:

a) The point estimate of the population proportion is 0.5544.

b) The margin of error is: 0.0320.

c) The interval is: (0.5224, 0.5864).

d) The interpretation of the interval is: we are 95% sure that the true population proportion is between 0.5224 and 0.5864.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which the variables used to calculated these bounds are listed as follows:

  • \pi is the point estimate of the population proportion.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

From the sample, the sample size and the point estimate are given as follows:

n = 929, \pi = \frac{515}{929} = 0.5544

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.5544(0.4456)}{929}}

M = 0.0320.

The interval is the point estimate plus/minus the margin of error, hence:

  • Lower bound: 0.5544 - 0.0320 = 0.5224.
  • Upper bound: 0.5544 + 0.0320 = 0.5864.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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The formula for an average rate of return is derived by dividing the average annual net earnings after taxes or return on the investment by the original investment or the average investment during the life of the project and then expressed in terms of percentage.

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