Answer:
between 0&1 and 2&3
Step-by-step explanation:
(Assuming that f(x) = 2x^2 - 5x + 1)
To solve this question we just need to find the zeros of the function f(x), and we do that by making f(x) = 0 and finding the values of x:
2x^2 - 5x + 1 = 0
Now we can use Bhaskara's formula:
Delta = b^2 - 4ac = 25 - 4*2 = 17
sqrt(Delta) = 4.12
x1 = (5 + 4.12) / 4 = 2.28
x2 = (5 - 4.12) / 4 = 0.22
the zero x1 = 2.28 is between 2 and 3, and the zero x2 = 0.22 is between 0 and 1, so the answer is 'between 0&1 and 2&3'
As the options A, B, C and D are not clear in the question text, you can just mark the option that has this result.
I’m going to try to answer these to the best of my ability.
1. Plane D
2. Plane C
3. AB
4. No
5. I don’t believe so because it doesn’t look like C is on the same plane as a AB and D.
6. I think so, yes! Collinear means that they are on the same line, and it looks like if you put a line between those two to connect them, they would connect perfectly!
7. B possibly? Because it looks like B, C, and D are all collinear and that they would pass through a straight line. A doesn’t look like it’s collinear with the rest of them.
8. No
9. Yes
10. Yes
I’m sorry if any of those are wrong, but I did make sure to try and put some explanations for some of them so you saw why I gave the answer that I gave! I hope that helped and like I said, I’m sorry if any of them are wrong, I tried my best!
?/8 = 3/?
Multiplying both sides by 8, then “?” gives
8? * ?/8 = 8? * 3/?
?*? = 24
The number, then, is sqrt(24), or 2 sqrt(6), which is approximately 4.90.
