<span>11/<span>12/13</span> Kg (mangoes)</span><span> is heavier than </span><span>11/<span>11/12</span><span> Kg (pineapples)</span></span>
Well, the greatest 2 digit number is 99, and the greatest 1 digit number is 9, so the awnser would be 108. Hope his helps.
Given :
C) is a circle of center O and radius R=2 cm, and A is a point such that OA=3 cm.
There exist two circles of center A and tangent to (C).
To Find :
The radius of the new circles.
Solution :
Since, OA is 3 cm .
So, first circle with tangent to C if centre is at A is OA itself.
First radius, r = 3 cm.
And second circle is the on with radius , R = 3 + 2 = 5 cm.
Therefore, the radius of both the circles are 3 cm and 5 cm.
Hence, this is the required solution.
Answer:
10
Step-by-step explanation:
Solving $4x=3y$ for $x$ gives $x = \frac{3}{4}y$. Substituting this into the desired expression gives\begin{align*}\frac{2x+y}{3x-2y} &= \frac{2\left(\frac34\right)y + y}{3\left(\frac34y\right) - 2y}\\
&=
\frac{\frac32y + y}{\frac94y - 2y} = \frac{\frac52y}{\frac{y}{4}} \\
&=\frac{5}{2}\cdot 4 = \boxed{10}.\end{align*}
Answer:
Step-by-step explanation:
![a.\\\frac{d}{dx}(\frac{-1}{1+x^2} )=\frac{d}{dx} [-1(1+x^2)^{-1}]=-1(-1)(1+x^2)^{-2}(2x)=\frac{2x}{(1+x^2)^2 }\\](https://tex.z-dn.net/?f=a.%5C%5C%5Cfrac%7Bd%7D%7Bdx%7D%28%5Cfrac%7B-1%7D%7B1%2Bx%5E2%7D%20%29%3D%5Cfrac%7Bd%7D%7Bdx%7D%20%5B-1%281%2Bx%5E2%29%5E%7B-1%7D%5D%3D-1%28-1%29%281%2Bx%5E2%29%5E%7B-2%7D%282x%29%3D%5Cfrac%7B2x%7D%7B%281%2Bx%5E2%29%5E2%20%7D%5C%5C)
b.
put 1+x²=u
2x dx=du
when x=0,u=1
when x=2,u=1+2²=5
