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nasty-shy [4]
3 years ago
5

On a map, Melbourne, Australia, is 22 centimeters from Sydney, Australia. The actual distance is 880 kilometers. If Canberra, Au

stralia, is 286 kilometers from Sydney, how far apart will they appear on the map, to the nearest centimeter?
Mathematics
1 answer:
Effectus [21]3 years ago
8 0

Answer:

Melbourne to Sydney is 22 centimeters on a map and 880 kilometers in real life. The conversion of map to land is 22:880. To find the difference of how far apart they are on a map we need to make another conversion.

Step-by-step explanation:

22:880 = map to real distance

Simplify conversion

1:40

1/40= x/286

Fill in Variable

1/40= 7.15/286

Hope this helped :)

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The daytime temperature in Apple Valley is falling by 2.5 degrees each day. What will the net change in the daily temperature be
nexus9112 [7]

Answer:

Option D -17.5 degrees is correct answer

Step-by-step explanation:

Since a calendar week has 7 days. and temperature is falling by -2.5 daily.

So, On Day 1 Temperature is -2.5 degrees

On Day 2 Temperature is -2.5 + -2.5 = -5 degrees

On Day 3 Temperature is = -5 + -2.5 = -7.5 degrees

On Day 4 Temperature is = -7.5 + -2.5 = -10 degrees

On Day 5 Temperature is = -10 + -2.5 = -12.5 degrees

On Day 6 Temperature is = -12.5 + -2.5 = -15 degrees

On Day 7 Temperature is = -15 + -2.5 = -17.5 degrees

So, Option D -17.5 degrees is correct answer.

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What is the slope of the line that contains the points (8, 3) and (8, 7)?
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The slope can be obtained by (y2 - y1) / (x2 - x1).  In this example, using the two points, we have
(7 - 3) /  (8 - 8 ) = 4 / 0.
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Two trucks started toward each other at the same time from towns 500 km apart. One truck traveled at a rate of 65 km per hour wh
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To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

So

Z = \frac{X - \mu}{\sigma}

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(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

0.167 = \frac{2.8}{\sqrt{n}}

0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

\sqrt{n} = 16.77

\sqrt{n}^{2} = 16.77^{2}

n = 281.23

We need a sample of at least 282 young men.

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