Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.

Mathematics

2 answers:

Fed [463]3 years ago

8 0

Step-by-step explanation:

again option D x = 10, y= 3

is the correct answer of this question.

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Digiron [165]3 years ago

3 0

Answer:

x = 10

y = 7

Step-by-step explanation:

4x-2 = x+28

4x-x = 28+2

3x = 30

x = 30÷3

x = 10

4y-7 = y+14

4y-y = 14+7

3y = 21

y = 21÷3

y = 7

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Will give brainliest to correct answer.

kirill [66]

It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: $(2 \sqrt{x} +1)^2=( \sqrt{x} +1)^2+(2 \sqrt{x} )^2$ . FOIL out the left side to get $4x+4 \sqrt{x} +1$ . FOIL out the first of the 2 expressions on the right to get $x+2 \sqrt{x} +1$ , and the second of the 2 to get 4x. Our equation now looks like this: $4x+4 \sqrt{x} +1=x+2 \sqrt{x} +1+4x$ . Combine like terms to get an equation that still has square roots in it that we have to deal with: $4x-x-4x=-2 \sqrt{x}$ and $x=2 \sqrt{x}$ . We will square both sides to get rid of the square root sign. $x^{2} =2x$ . This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. $x^{2} -2x=0$ . Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2

3 0

3 years ago

Read 2 more answers

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makkiz [27]

Answer: 1st option

Step-by-step explanation:

I've attached the solution