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RUDIKE [14]
3 years ago
6

2n +5)=2 Help me please

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer:

-1.5

Step-by-step explanation:

Grace [21]3 years ago
3 0

Answer:

N=<u> </u>

<u>-  \frac{3}{2}</u>

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For each function, state the vertex and whether the function has a maximum or minimum value. Explain how you decided? f(x) = -(x
nordsb [41]

Answer:

maximum value at (- 1, 6 )

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

• If a > 0 then minimum value

• If a < 0 then maximum value

y = - (x + 1)² + 6

with (h, k) = (- 1, 6 ) and a = - 1

Thus vertex = (- 1, 6 ) and is a maximum

4 0
3 years ago
NEED HELP ASAP PLEASE WITH #2!
AleksandrR [38]

Answer: The answer is the first bubble

Step-by-step explanation:

1. When you identify the pairs you get: { ( -5,-4), (-1,5), ( -5,3) , (7,8) }

2. When figuring out whether or not it is a function, you have to see if there are any same y values. If there is no y values that are the same, then the relation is a function.

3. This relation is a function.

* Also, if you have a relation that has the two or more of the same x values, the relation is still a function no matter what.

4 0
3 years ago
Factorize completely the expression(h+2k)²+4k²-h²​
julsineya [31]

The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

From the question,

We are to factorize the expression (h+2k)²+4k²-h²​ completely

The expression can be factorized as shown below

(h+2k)²+4k²-h²​ becomes

(h+2k)² + 2²k²-h²​

(h+2k)² + (2k)²-h²​

Using difference of two squares

The expression (2k)²-h²​ = (2k+h)(2k-h)

Then,

(h+2k)² + (2k)²-h²​ becomes

(h+2k)² + (2k +h)(2k-h)

This can be written as

(h+2k)² + (h +2k)(2k-h)

Now,

Factorizing, we get

(h +2k)[(h+2k) + (2k-h)]

Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

Learn more here:brainly.com/question/12486387

5 0
3 years ago
Read 2 more answers
Determine the relative order of the metric prefixes of kilo-, micro-, centi-, and milli-.
nadya68 [22]

The relative order of the metric prefixes is micro-, milli-, centi- and  kilo-,

<h3>What are metric units?</h3>

Metric units are units used to measure quantities

The units are given as:

kilo-, micro-, centi-, and milli-

In metric units, the value of each prefix is:

Kilo = 1000

Micro = 0.0001

Centi = 100

Milli = 0.1

In order of arrangement, we have:

Micro = 0.0001

Milli = 0.1

Centi = 100

Kilo = 1000

Hence, the relative order of the metric prefixes is micro-, milli-, centi- and  kilo-,

Read more about metric units at:

brainly.com/question/2555957

8 0
2 years ago
When looking at the median of a data set, what information do you get when looking at the median?
cestrela7 [59]
You get the middle of all the data while looking at the median of a data set!

I hope this helped! Mark me Brainliest! :) -Raven❤️
7 0
3 years ago
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