(a) The sum of length and width is half the perimeter, so the breadth in terms of length (x) in cm will be
.. breadth = 34 -x
(b) Then the expression for the area (in cm^2) is
.. area = length*breadth
.. 253 = (x)(34 -x)
.. x^2 -34x +253 = 0 . . . . . subtract the right side, eliminate parentheses
.. (x -11)(x -23) = 0 . . . . . . . factor
.. x = 11 or 23
The dimensions of the rectangle are 11 cm by 23 cm.
1) V.A, J.L, C.T, R.R, T.Mc
2) J.L, R.R, C.T, V.A, T.Mc
3) C.T, J.L, R.R, V.A, T.Mc
4) C.T, V.A, T.Mc, J.L, R.R
5) C.T, V.A, J.L, T.Mc, R.R
Answer:
there are 2 terms in this expression
THEN, LENGTH OF THE HYPOTNUSE IS 5 FEET.
1. 4n-6
2.$50-x
3.whole number
4.distrutive
5.13a+3
6.$50.00+$20.00+2($35.0<span>0) -2 ($10.00) = $120.00</span>
