PLS HELP!! There are 8 lifesavers in a roll and 3 of them are red. What is the probability of opening the roll and the 1st lifes
aver is red? Write as a percent. (Only one end of the roll can be opened)
2 answers:
ANSWER:
Total no. of lifesavers = 8
Red lifesavers = 3
So, Probability of getting red lifesaver are
Answer:
37.5 percent (3/8)
Step-by-step explanation:
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Answer:
6 1/4
Step-by-step explanation:
so from 190.1 to 201.5 is 201.5 - 190.1 = 11.4.
now, if we take 190.1 as the 100%, what is 11.4 off of it in percentage?
#1
- B²=15²-7²
- B²=225-49
- B²=176
- B=13.26(exact)
- B=13.3(approx)
#2
- B²=17²-7²
- B²=289-49
- B²=240
- B=15.49(exact)
- B=15.5
#3
- H²=20²+14²
- H²=400+196
- H²=596
- H=24.41(approx)
- H=24.4(exact)
#4
- B²=6²-3²
- B²=36-9
- B²=27
- B=5.196(exact)
- B=5.2(approx)
Each person would get 1 2/3 bags of chips.
Answer:
bet I will
Step-by-step explanation:
