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ollegr [7]
3 years ago
6

(04.02 MC)

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

Hi! The answer to your question is B. (0,3)

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

☆Brainliest is greatly appreciated!☆

<em>Hope this helps!!</em>

<em>Stay Safe!!</em>

<em>- Brooklynn Deka</em>

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There are 13 books on a shelf. 6 of these books are new. (a) What is the ratio of new books to used books? (b) What is the ratio
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If 6 of the 13 books are new, then 7 of them are used. The ratio of new (6) to used (7) is

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Ratio of all books (13) to used books (7) is

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A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

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3 years ago
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the equation will be:
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