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schepotkina [342]
3 years ago
10

1. Find all the zeros of the polynomial P(x) = 2x^3 – x^2 – 4x+3​

Mathematics
2 answers:
umka21 [38]3 years ago
4 0

Answer:

nicce

Step-by-step explanation:

Firlakuza [10]3 years ago
4 0
Since -1 is a zero, (x+1) is a factor.
If you know how to do polynomial division, you can divide P(x) by (x+1) to give a quadratic.
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marin [14]

Answer:

Step-by-step explanation:

From the table attached,

x-intercept of the linear function is, the value of 'x' when f(x) = 0  

x = 3 [x-intercept]

Function 'g' is the sum of 2 and the cube root of the sum of three time x and 1.

g(x) = 2+\sqrt[3]{3x+1}

For x-intercept,

g(x) = 0

2+\sqrt[3]{3x+1}=0

3x + 1 = (-2)³

3x + 1 = -8

3x = -8 - 1

3x = -9

x = -3

Therefore, the x-intercept of function 'f' is different or greater than the x-intercept of function g.  

4 0
2 years ago
The model builder has 4 pieces of balsa wood that are 4 cm, 5 cm, 6 cm, and 7 cm length. How many different combinations of 3 pi
s2008m [1.1K]
About 22 i think hope it helps in any way

7 0
3 years ago
When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is
Pie

Answer:

B)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If you are asked to provide a set of two or more numeric answers, separate them with commas. For example, to provide the year th
garik1379 [7]

Answer:  Perimeter = 66 cm and area =66\ m^2

Step-by-step explanation:

The perimeter of rectangle is given by :-

P=2(l+w), where l is length and w is width of the rectangle.

Given : A rectangle has a length of 5.50 m and a width of 12.0 m .

Then, the perimeter of rectangle :

P=2(12+5.50)\\\\\Rightarrow\ P=2(17.50)=35\ m

Also, area of rectangle is given by :-

A=l\times w=5.50\times12=66 \ m^2

Area of rectangle = 66\ m^2

3 0
3 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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