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ella [17]
2 years ago
9

Find the equation of the linear function represented by the table below in slope-

Mathematics
1 answer:
masha68 [24]2 years ago
7 0

Answer:

y = -2x + 4

Step-by-step explanation:

N/A

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Hey i need help (winner gets crowned brainlyest)
Alenkinab [10]

Answer:

Step-by-step explanation:

13) x⁴-12x² +36    

(a-b)² = a²-2ab+b²

a = x² ; b = 6

(x²)² - 2 * x² * 6 + 6² =  (x² - 6)²

14) w⁴- 14w² - 32 =     w⁴+ 2w² - 16w² - 32  = w² (w² + 2) - 16 (w²+2)

                           = (w² + 2) (w² -16 )

15) k³ + 7k² - 44k = k ( k² + 7k -44)  = k ( k+11 ) ( k-4 )

16) 2a³ +28a²+96a =2a(a²+14a+48) = 2a(a+6)(a+8)

17) -x³ +4x² +21x = (-x) ( x² - 4x - 21) = (-x)(x-7)(x+3)

18) m⁶ - 7m⁴ -18m² = m² ( m⁴-7m²-18) = m² (m²-9)(m²+9)

                             = m² (m+1) (m-1)(m²+9)

19) 9y⁶ +6y⁴ + y²= y² ( 9y⁴+6y²+1) = y² (3y²+1)²

20) 8c⁴+10c² -3 = (4c +1)(2c-3)

3 0
3 years ago
Which postulate proves the two<br> triangles are congruent?
sammy [17]

Answer:

<em>AAS</em>

Step-by-step explanation:

<em>because</em><em> </em><em>here </em><em>it </em><em>is </em><em>given</em><em> </em><em>that </em><em>two </em><em>angle </em><em>are</em>

<em> </em><em>equal</em>

and a side is common between both traingle

so, both traingle are congruent by

<em><u>AAS</u></em>

hope it helps

5 0
2 years ago
What is 40,023,032 in expanded form
prohojiy [21]
40000000+20000+3000+30+2 zero's dont matter
7 0
3 years ago
Read 2 more answers
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
Combime like terms to create an equivalent expression -2.5(4x-3)​
Ann [662]

Answer: -10x+7.5

Step-by-step explanation:

First multiply -2.5(4x)= -10x and then -2.5x-3= 7.5 it should be -10x+7.5

3 0
3 years ago
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