3 years ago

Determine whether the given value is a solution of the equation. Show your work.

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

Step-by-step explanation:

No Not an answer

21=x-5

x=26

You might be interested in

Triangle DEF is congruent to D'EF' by the SSS theorem. Which single rigid transformation is required to map DEF onto D'EF'?

lions [1.4K]

The answer is rotation

3 0

3 years ago

Read 2 more answers

Evaluate 5|x^3 - 2| + 7 when x = -2

Dafna1 [17]

Answer:

Step-by-step explanation:

5 |-2^3 - 2| + 7

-2^3 = -8

-8 - 2 = -10

absolute value of -10 = 10

5 * 10 = 50

50 + 7 = 57

7 0

3 years ago

Read 2 more answers

Samaria has 6 more than three times as many pieces of candy as sydney. samaria has 36 pieces of candy. how many does sydney have

lesya [120]

For this case we have:

x: Number of candies that Sydney has

The equation to find the amount of Sydney sweets is given by:

$3x + 6 = 36$

We want to clear x:

$3x = 36-63x = 30$

$x = \frac{30}{3}$

$x = 10$

So, Sydney has 10 candies

Answer:

Sydney has 10 candies

4 0

3 years ago

Read 2 more answers

Helpppppppp due todayyyy

dimaraw [331]

B I think please give me brainliest

6 0

3 years ago

Read 2 more answers

When will the equation p(b)=520(0.88)^b have a value less than 100?

yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × $0.88^{b}$ to have a value less than 100 we can establish inequality as:

p(b) < 100

or, 520 × $0.88^{b}$ < 100

or, $\frac{520}{520}$ × $0.88^{b}$ < $\frac{100}{520}$

or, $0.88^{b}$ < $\frac{1}{5.2}$

or, ㏒ ( $0.88^{b}$ ) < ㏒ ( $\frac{1}{5.2}$ )

or, b× ㏒ 0.88 < ㏒ ( $\frac{1}{5.2}$ )

or, $\frac{log (\frac{1}{5.2}) }{log (0.88)}$ < b

or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0

3 years ago