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3 years ago

Need help with this problem!!!!

Mathematics

1 answer:

beks73 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

you can get a lot more of a good relationship is a different type and have different effects and then use it for yourself to be able that it doesn't have different benefits to smome and the differences are the claire group is that it will

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WILL.MARK BRAINLEST. ( The length of a rectangular garden is 5m longer than its breadth .If its perimeter is 150 m,find the area

inessss [21]

Answer:

1400m^2

Step-by-step explanation:

Solution,

Let the breadth of the rectangle be x m, then the length of the rectangle will be x+5 m,

Now,

Perimeter of the rectangle=2(l+b)

150=2(x+5+x)

150=2(2x+5)

150=4x+10

150-10=4x

140=4x

140/4=x

35=x

So, the breadth of the rectangle=35 m

and length=(35+5)m=40m

Again,

Area of the rectangle=l×b

=40m×35m

=1400 m^2

I hope it helped U

stay safe stay happy

3 0

3 years ago

Read 2 more answers

clara wants to run a total of 5 1/2 miles each lap around the track is 0.25 miles. how many laps around the track does clara nee

NemiM [27]

Answer:

22 laps

Step-by-step explanation:

Clara wants to run 5 1/2 miles, and the track is only 0.25 miles long. This is a fairly easy question, you just need to figure out how many times 5 1/2 goes into 0.25, because she wants to run that amount of miles (I could never run that much).

I hope that answers your question so you understand, and I hope you have a great rest of your day! :)

5 0

4 years ago

Question 5 (25 points)

DiKsa [7]

Answer:

Again its C like i answered before.

Step-by-step explanation:

Cos is adj/hyp and there is only one cos option so it must be correct.

7 0

3 years ago

The energy information administration reported that the mean retail price per gallon of regular grade gasoline was $3.43. Suppos

Morgarella [4.7K]

Answer:

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

2.28% of regular grade gasoline sold for more than $3.63 per gallon

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 3.43, \sigma = 0.1$

What percentage of regular grade gasoline sold between $3.33 and $3.53 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.53

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.53 - 3.43}{0.1}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 3.33

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.33 - 3.43}{0.1}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

What percentage of regular grade gasoline sold between $3.33 and $3.63 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.63

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.63 - 3.43}{0.1}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 3.33

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.33 - 3.43}{0.1}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.9772 - 0.1587 = 0.8185

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

What percentage of regular grade gasoline sold for more than $3.63 per gallon?

This is 1 subtracted by the pvalue of Z when X = 3.63. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.63 - 3.43}{0.1}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of regular grade gasoline sold for more than $3.63 per gallon

3 0

3 years ago

ASAP

muminat

Answer:

a) $\left \{ {{8x+218=y} \atop {5x+521=y}} \right.$ , b) $101

Step-by-step explanation:

Hermes: 8 envelopes, $218

Apollo: 5 envelopes, $521

If x is the amount in each envelope, H is the amount Hemes has and A is the amount Apollo has, this would be a possible system of equations.

$\left \{ {{8x + 218 = H} \atop {5x +521 = A}} \right.$

If Apollo and Hermes both had the same amount of total money, A and H could equal y

$\left \{ {{8x+218=y} \atop {5x+521=y}} \right.$

We want to find the amount in each envelope (x), so we can substitute y in the first equation for y in the second equation:

$8x+218=5x+521$

Subtract $5x$ from both sides

$3x+218=521$

Subtract 218 from both sides

$3x=303$

Divide both sides by 3

$x=101$

So there would have to be $101 in both envelopes for Apollo and Hermes to have the same amount of total money.

7 0

3 years ago