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stepan [7]
3 years ago
8

Ive been trying to figure out this problem, I’m not sure if each fruit is measures per pound. Please help!

Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0

Answer:

e

Step-by-step explanation:

i will give free points to people who answer my problem

vichka [17]3 years ago
4 0

Answer:

Elena spent p-3.45 more than Taniy

Step-by-step explanation:

LET THE PRICE OF CHERRY PER POUND BE "p" !!!!!

Elena bought a watermelon for = $7.75

Elena bought 3 pounds of cherry for = $3p

Total money spent by Elena = 3p + 7.75

Taniy bought a pineapple for = $4.35

Taniy bought 2 pounds of cherry for = $2p

Total money spent by Taniy = 2p + 4.35

More money spent by Elena than Taniy =

(3p+7.75)-(2p+4.35)\\=>3p+7.75-2p-4.35\\=>3p-2p+7.75-4.35\\=>p-3.45

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3 years ago
Which of these expressions can be used to calculate the monthly payment for
Mandarinka [93]

Answer:

1326632.865

Step-by-step explanation:

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4 years ago
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Lady_Fox [76]

Answer:

<u>12n + 2</u>

Step-by-step explanation:

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3 years ago
Solve for x.<br><br> 2/5 x = 6/5
Alexxandr [17]

Answer: 15/5 or 3

Step-by-step explanation:

2/5x =6/5

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3 years ago
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Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.
laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

6 0
3 years ago
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