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3 years ago

B/4 +2 = -1 what is the value of b

Mathematics

1 answer:

trapecia [35]3 years ago

7 0

Answer:b= -12

Step-by-step explanation:

b/4 + 2 = -1

First subtract 2

b/4 = -3

Then multiply by 4

b= -12

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The base of a parallelogram is (2x + 3) units and the corresponding height is (3x – 2) units. Find the area of the parallelogram

Maslowich

Answer:

S = 6x² + 5x - 6

5544 sq. units

Step-by-step explanation:

Area of parallelogram is:

S = bh

Given:

b = 2x+3
h = 3x -2

Then:

S = (2x + 3)(3x - 2) =
6x² - 4x + 9x - 6 =
6x² + 5x - 6

S = 6x² + 5x - 6

If x = 30, then plug it in the equation:

S = 6*30² + 5*30 - 6 = 5544 sq. units

4 0

3 years ago

Mrs. Hernandez earns $35.60 per hour and in one week earned $854.40. For how many hours did she work last week? What expression

zmey [24]

Answer:

Option A

Step-by-step explanation:

Given the following question:
Mrs. Hernandez earns $35.60 an hour
One week she earned $854.40

To find the answer we divide 8,544 by 356

$8544\div356=24$
$854.40\div35.60=24$

Mrs. Hernandez worked "24 hours last week" by using the first options equation, we can find that answer.

Hope this helps.

4 0

2 years ago

The face of a clock has a circumference of 63 in. What is the area of the face of the clock?

ryzh [129]

Answer:

The area of the clock $= 315.41\ inch^{2}$

Step-by-step explanation:

We have been given the face of the clock that is $63\ in$

So that is also the circumference of the clock.

Since the clock is circular in shape.

So $2\pi(r)=63\ inch$

From here we will calculate the value of radius $(r)$ of the clock that is circular in shape.

Then $2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in$

Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.

Now $\pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}$

So the area of the face of the clock = $315.41\ in^{2}$

6 0

3 years ago

Find the length of segment AB

fredd [130]

Answer:

question 8: AB = 25 units

wuestion 9: CD = √89 o.r. ≈ 9.4339

explanations in image :)

4 0

3 years ago

In a candy factory, nutty chocolate bars contain 22.0% by mass pecans. If 4.5 kg of pecans were used for candy last Tuesday, how

Zanzabum

So we know that 22% of the mass off the chocolate bars is pecans, and that 4.5kg of pecans were used. To find the mass of nutty chocolate bars made with 4.5kg of pecans we can divide the 4.5 by 22 to find 1% of the weight of nutty chocolate bars produced, then multiply it by 100 to find the full weight in kg.

So 4.5/22= 0.205 (3dp), then 0.205x100=20.5kg of nutty chocolate bars produced.

Now to convert the kgs of chocolate bars to lbs, we multiply by 2.205 (as there is approximately 2.205 lbs to 1 kg).

So 2.205x20.5kg=45.203 lbs (3dp) of nutty chocolate bars produced on Tuesday.

4 0

3 years ago