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Mathematics

1 answer:

Ghella [55]2 years ago

8 0

Answer:

x = 8, so 6x = 48 and 4x + 10 = 42

Step-by-step explanation:

This is a right angle, so we can say that 6x + 4x + 10 = 90 = 10x + 10 = 90 = 10x = 80 = x = 8.

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Y=log(x-3) what would be the base?

timurjin [86]

By definition, if :

$a^y = b$

$y = log_a b$

We highlight the following elements:

a = Base of the logarithm;
b = logarithmand or antilogarithm
y = logarithm

Therefore:

Note that since the base was not specified, we know that it is equal to 10.

$y = log_a b$
$y = log_{10} (x-3)$
$10^y = (x-3)$

Answer:

Base of the logarithm = 10

4 0

3 years ago

. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a

crimeas [40]

Answer:

The base and height of the garden are 4.60 ft and 5.60 ft.

Step-by-step explanation:

The area of the garden is, A = 24 ft².

The base height of the garden are:

base (b) = 6x - 4

height (h) = x + 3

Compute the value of x as follows:

$A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\$

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

$x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{ 3 } \pm \frac{ \sqrt{139}\, }{ 3 }\\x = 1.59661\\x\approx 1.60$