Answer:
A=112 in. squared
Step-by-step explanation:
A=bxh=14·8=112
To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:

<u>Rectangle (a)</u>


<u>Rectangle (b)</u>


<u>Rectangle (c)</u>


<u>Rectangle (d)</u>


Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
Answer:
See below
Step-by-step explanation:
Start by subtracting 5.2 from both sides of the equation
so "subtraction property of equality " I suppose ......
then the next step would be divide both sides by 2.5
which would be division property of equality
-3 • (5x + 2y = 7)
-15x - 6y = -21
-2x + 6y = 9
__________
-17x = -12
x = 12/17
5(12/17) + 2y = 7
2y = 7 - 60/17
2y = 3.47
y = 1.735
Answer:
2
Number line.
We start at -6 or -8.
If we start from -6, we will be going __ spaces to the left until we get to -8.
Or start from -8 and go __ spaces to the right until you get to -6.
Then count the spaces.
You'll get 2.