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2 years ago

An angle that is one half its arc is a/n

1 answer:

4 0

The answer is inscribed

The measure of an inscribed angle is half the measure of the intercepted arc. That is, m∠ABC=12m∠AOC. This leads to the corollary that in a circle any two inscribed angles with the same intercepted arcs are congruent.

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I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5

Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2): y - 3x/4 = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

4 0

3 years ago

HELP PLEASE!!!! <br> WILL GIVE BRAINLIEST <br> ANY LINKS OR WRONG ANSWERS WILL BE REPORTED!!!!

jarptica [38.1K]

Answer:

The numerator is 70.

Step-by-step explanation:

70% converts to the fraction of 70/100. Therefore, the numerator is 70.

Hope you have a great day,

Ginny

3 0

2 years ago

Read 2 more answers

HELP ME PLEASE

Sidana [21]

$1:500,000 = 8 : 8*500,000 = 8:4,000,000\\4,000,000 cm = 40 km$

4 0

2 years ago

Benjamín made 3 times more than Alberto and Carlota 2 times more than Benjamín, so how much is it, help me

vichka [17]

Step-by-step explanation:

you are "hiding" some more information (like how much they made together).

without that we cannot calculate the actual values.

all I can do is set up the equations expressing the given relations between the parts of the total :

a = amount Alberto made

b = amount Benjamin made

c = amount Carlota made

b = 3×a

c = 2×b = 2× 3×a = 6×a

that's it.

your see ? now we need something that "ties" all 3 together, an equation of all 3 variables, where we can use the first 2 equations (by substitution) and then solve for the remaining third variable.

and that is missing.

if it is something like "together they made x", then we would have

a + b + c = x

a + 3a + 6a = x

10a = x

a = x/10

b and c we get then from the first 2 equations by simply using the calculated value of a :

b = 3×(x/10) = 3x/10

c = 6×(x/10) = 6x/10 = 3x/5

7 0

2 years ago

On a March day the temperature changed by an average of -0.5° C per hour from its high of 5° C at 1:00 pm. What was the temperat

pychu [463]

0°? seems like it if you were to sub 0.5 ten times from 5

5 0

2 years ago