Ask question

Ask question

All categories

2 years ago

7

PLEASE HELP WILL GIVE BRAINLIST

1 answer:

Neko [114]2 years ago

4 0

Answer:

b= -1/4

Step-by-step explanation:

I just get it on a work a day ago good luck

You might be interested in

7. Are the two lines parallel, perpendicular, or neither? Explain your answer. Show work needed to answer the

kiruha [24]

Answer:

The lines are perpendicular

Step-by-step explanation:

5 0

2 years ago

9. A waffle iron can make a waffle in 4 minutes. How many waffles can be made in an hour?

Sati [7]

Answer:

15. 15x4=60

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

How do you connect the ideas of congruency and rigid motion and how do you prove congruency?

larisa86 [58]

If you cut a triangle out of a piece of paper, and move that triangle around (sliding, rotating, reflecting) then that triangle will retain its original shape and size. The three movement types mentioned are rigid motions. They do not change the size or shape of the triangle. If two triangles are congruent, then a sequence of one or more rigid motions can be applied to have them line up together.

7 0

3 years ago

Find the approximate side length of a square game board with an area of 186in2

Arturiano [62]

13.6in is the answer

8 0

3 years ago

Read 2 more answers

Identify a pattern in the given list of numbers. Then use this pattern to find the next number.

Rom4ik [11]

Answer:

The given sequence is geometric sequence

In the given pattern we have next number is $a_5=\frac{1}{4}$

Step-by-step explanation:

Given numbers are 64,-16,4,-1

To identify the pattern of the given numbers :

Let $a_1=64$ , $a_2=-16$ , $a_3=4$ and $a_4=-1$

To find the next number that is $a_5$

common ratio $r=\frac{a_2}{a_1}$

$=\frac{-16}{64}$

$r=-\frac{1}{4}$

$r=\frac{a_3}{a_2}$

$=\frac{4}{-16}$

$r=-\frac{1}{4}$

Therefore the common ration is $r=-\frac{1}{4}$

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is $a_n=a_1r^{n-1}$

Now find the 5th term so put n=5 , $a_1=64andr=\frac{-1}{4}$ we have

$a_5=64(\frac{-1}{4})^{5-1}$

$=64(\frac{-1}{4})^{4}$

$=64(\frac{1}{4})^{4}$

$=64(\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4})$

$=\frac{1}{4}$

Therefore $a_5=\frac{1}{4}$

8 0

3 years ago