Question

A family on vacation drives 123 miles in 2 hours, then gets stuck in traffic and goes 4 miles in the next 15 minutes . The remaining 191 miles of the trip take 3 3/4 hours. What was their average rate of speed to the nearest tenth of a mile per hour ?

Answer 1

The average speed of an object is the total distance traveled by the object divided by the elapsed time to cover that distance.

Total distance traveled = 123 miles + 4 miles + 191 miles = 318 miles

Total time taken = 2 hours + 15 minutes + $3\frac{3}{4}$ hours

= 2 hours + $\frac{15}{60}$ hour + $\frac{15}{4}$ hours

= $2+\frac{1}{4}+\frac{15}{4}$ hours

=$2+\frac{16}{4}$ hours

= 6 hours

Average speed = Total distance $\div$ Total time

= $\frac{318}{6}$ mile per hour

= 53 mile per hour.

Answer 2

I wish i could help but i can't sorry

Answer 3

The average speed of an object is the total distance traveled by the object divided by the elapsed time to cover that distance.

Total distance traveled = 123 miles + 4 miles + 191 miles = 318 miles

Total time taken = 2 hours + 15 minutes + $3\frac{3}{4}$ hours

= 2 hours + $\frac{15}{60}$ hour + $\frac{15}{4}$ hours

= $2+\frac{1}{4}+\frac{15}{4}$ hours

=$2+\frac{16}{4}$ hours

= 6 hours

Average speed = Total distance $\div$ Total time

= $\frac{318}{6}$ mile per hour

= 53 mile per hour.