The least common multiple is 63.
Explanation: 63 is the least number that 3 7 and 9 can go into evenly. Therefore, it is the least common multiple.
The limit is the y value that the graph approaches from both sides as x approaches the target limit
it they approach different values from the left and right sides, the limit does not exist
we want to find the limit as x approaches 5
we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5
evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0
f(5)=8
f(x)=x+3
f(5)=5+3
f(5)=8
it approaches 0 and 8 from both sides
the limit doesn't exist
D
Answer:
9.4
Step-by-step explanation:
How to find the mean of a data set: Add each number in the set together. Then divide the sum of all of the numbers by how many numbers there are.
Answer:
5. x = -1
6. x = 2
Step-by-step explanation:
5. AB = 5
BC = 2x + 6
AC = x + 10
AB + BC = AC (segment addition postulate)
5 + 2x + 6 = x + 10 (substitution)
Collect like terms
5 + 6 + 2x = x + 10
11 + 2x = x + 10
2x - x = - 11 + 10
x = -1
6. AB = 9x + 7
BC = -3x + 20
AC = 39
AB + BC = AC (segment addition postulate)
(9x + 7) + (-3x + 20) = 39 (substitution)
Solve for x
9x + 7 - 3x + 20 = 39
Collect like terms
9x - 3x + 7 + 20 = 39
6x + 27 = 39
Subtract 27 from both sides
6x + 27 - 27 = 39 - 27
6x = 12
Divided both sides by 6
6x/6 = 12/6
x = 2
S=2LW+2LH+2WH
First, subtract 2LH from both sides
S-2LH=2LW+2LH-2LH+2WH
S-2LH=2LW+2WH
Separate out the W
S-2LH=W(2L+2H)
Divide by 2L+2H to get W alone

Hope this helps.