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klemol [59]
3 years ago
8

A discount store marks down all of its holiday merchandise by 20% off the regular selling price. Find the discounted price of de

corations that regularly sell for $16 and $23. Write an equation to represent this situation and use it to answer the question.
Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

1. $16 = $320

2. $23 = $460

Step-by-step explanation:

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You have 512 cubic feet of chocolate pudding. You have an empty cube that you want to fill with pudding; it measures 7 feet per
max2010maxim [7]
Well it would mostly be 73.14..
8 0
3 years ago
How do i solve for x?
Oxana [17]

Answer:

x = 10

Step-by-step explanation:

You have to divide 30 divided by 10 is 3 so ya.

7 0
3 years ago
Read 2 more answers
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
3 years ago
Let the random variable Q represent the number of students who go to a certain teacher's office hour each day. The standard devi
postnew [5]

Answer: А. On average, the number of students going to an office hour varies from the mean by about 2.2 students

Step-by-step explanation:

The standard deviation is a measure of spread, which gives how values deviate from the average or mean value of a particular distribution. Hence, the standard deviation is usually defined about the average value of a distribution.

Therefore, for a certain random variable representing the number of student who visits office hours, the standard deviation will be defined about the average or mean value of the random variable Q.

Thus, stated as ; number of students going to an office hour varies from the mean by 2.2 on average.

4 0
2 years ago
Read 2 more answers
A hockey team is convinced that the coin used to determine the order of play is weighted. The team captain steals this special c
fredd [130]

Answer:

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.

Step-by-step explanation:

Let p be the probability of heads in a single toss of the coin. Then our null hypothesis that the coin is fair will be formulated as

H0 :p 0.5   against   Ha: p ≠ 0.5

The significance level is approximately 0.05

The test statistic to be used is number of heads x.

Critical Region: First we compute the probabilities associated with X the number of heads using the binomial distribution

Heads (x)        Probability (X=x)                        Cumulative     Decumulative

0                        1/16384 (1)             0.000061     0.000061

1                         1/16384  (14)         0.00085             0.000911

2                       1/16384 (91)           0.00555             0.006461

3                       1/16384(364)         0.02222

4                       1/16384(1001)         0.0611

5                       1/16384(2002)       0.122188

6                        1/16384(3003)      0.1833

7                         1/16384(3432)      0.2095

8                        1/16384(3003)       0.1833

9                        1/16384(2002)       0.122188

10                       1/16384(1001)        0.0611

11                       1/16384(364)        0.02222

12                      1/16384(91)            0.00555                             0.006461

13                     1/16384(14)              0.00085                           0.000911

14                       1/16384(1)            0.000061                            0.000061

We use the cumulative and decumulative column as the critical region is composed of two portions of area ( probability) one in each tail of the distribution. If  alpha = 0.05 then alpha by 2 - 0.025 ( area in each tail).

We observe that P (X≤2) =   0.006461 > 0.025

and

P ( X≥12 ) = 0.006461 > 0.025

Therefore true significance level is

∝=  P (X≤0)+P ( X≥14 ) = 0.000061+0.000061= 0.000122

Hence critical region is (X≤0) and ( X≥14)

Computation x= 12

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.

3 0
3 years ago
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