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klasskru [66]
3 years ago
6

A company logo has 4 concentric circles. Suppose you graph the points (diameter, circumference) and connect them with a line. In

terms of pi, what is the slope of the resulting line?
Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

Step-by-step explanation: they will form a straight line, passing through the origin.

let the radius of the first one be r

then the first point is (2r, 2πr)

slope of line passing through (0,0) and (2r, 2πr)

= (2πr)/(2r)

= π

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solve this word problem leading to quadratic equation: the area of a rectangle is 60cm². The length is 11cm more than the width.
morpeh [17]

Answer:

Step-by-step explanation:

let : x The length and y the width you have this system :

xy =60....(1)

x = y+10...(2)

put the value for x in (1):  (y+10)y =60

the quadratic equation is : y² +10y - 60 = 0

Δ =b² - 4ac        a = 1        b= 10      c= - 60

Δ =10² - 4(1)(-60) = 324 =18²

y 1 = (-10-18)/2 negatif...... refused

y 2 = (-10+18)/2 =4

the width is 4

8 0
3 years ago
2x+7=16<br> as a improper fraction simplified
lara31 [8.8K]

Answer:

9/2 or 4.5

Step-by-step explanation:

8 0
3 years ago
ANSWER BOTH CORRECTLY!! PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP THERE IS 2 QUESTIONS
melomori [17]

Answer:

TS = 22

x = 49

Step-by-step explanation:

(5x-2)/39 = (3x+1)/26

Multiply both sides by 78:

10x-4 = 9x+3

x=7

3x+1 = 22

:::::

(x+5)/36 = 30/20

x+5 = 54

x = 49

7 0
3 years ago
Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont
Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

f(x) = x^{3}-9\cdot x^{2}+ 3, 2 \leq x \leq 12

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

f'(x) = 3\cdot x^{2}-18\cdot x

3\cdot x^{2}-18\cdot x = 0

3\cdot x \cdot (x-6) = 0 (Eq. 1)

As we can see, only a solution is a valid critical value. That is: x = 6

Second, we determine the second derivative formula and evaluate it at the only critical point:

f''(x) = 6\cdot x -18 (Eq. 2)

x = 6

f''(6) = 6\cdot (6)-18

f''(6) =18 (Absolute minimum)

Third, we evaluate the function at each extreme of the given interval and the critical point as well:

x = 2

f(2) = 2^{3}-9\cdot (2)^{2}+3

f(2) = -25

x = 6

f(6) = 6^{3}-9\cdot (6)^{2}+3

f(6) = -105

x = 12

f(12) = 12^{3}-9\cdot (12)^{2}+3

f(12) = 435

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

6 0
3 years ago
If you want to buy an item in a store that costs $32.50 and is on sale for 30% off, then how much would the item actually cost y
creativ13 [48]

Answer:

$22.75

Step-by-step explanation:

(Original price) is 100%

New price: 100%-30%(discount)=70%

(0.70)*($32.5)=$22.75

6 0
3 years ago
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