Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
Answer:
15 gallons
Step-by-step explanation:
Given that:
Pumping rate is modeled by the equation :
Q(t)=45-t gallons per minute ; where t is in minutes
Number of gallons in tank after 30 minutes ;
Q(t)=45-t
Q(30) = 45 - 30
Q(30) = 15
Hence, Number of gallons in tank after 30 minutes is 15 gallons
So first step is to simplify everything outside of the radicals.
6*2=12
:. The expression is
__ __
12*\| 8 * \| 2
Now we know that
__ __ __
\| 8 = \| 4 * \| 2
And
__ __
\| 2 * \| 2 = 2
And
__
\| 4 = 2
So if we incorporate what we know into the equation, we can figure it out.
So let's first expand the radical 8.
__ __ __
12*\| 4 * \| 2 * \| 2
Now by simplifying the radical four and combining the radical twos, we can get all whole numbers.
12*2*2
Which equals 48.
Answer:48
This is the answer with the correct work.
First convert 5 1/3 into a fraction which is 16/3.
16/3 divided by 7/8 is the same as 16/3 multiplied by 8/7. So you multiply the fractions together to get 128/21.
