2 years ago

5. Write a function of the form f(x) = - + k with a vertical asymptote at x = -15 and a horizontal asymptote of y = -6.

Mathematics

1 answer:

Amanda [17]2 years ago

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DONT TRUST LINK!! IT IS USED TO STEAL PERSONAL INFORMATION

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Step-by-step explanation:

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Look at the figure, FHJM. find the length of HJ

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Step-by-step explanation:

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At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

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3 years ago

5. Write a function of the form f(x) = - + k with a vertical asymptote at x = -15 and a horizontal asymptote of y = -6.​

5. Write a function of the form f(x) = - + k with a vertical asymptote at x = -15 and a horizontal asymptote of y = -6.