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3 years ago

I WILL MARK BRAINIEST AND GIVE 100 POINTS IF ANSWERED ASAP. What is the measure of TYV?

Mathematics

1 answer:

sesenic [268]3 years ago

7 0

Answer:

the answer is 116 jdsjosbdo

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Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

4 years ago

What's the quadratic equation?

erma4kov [3.2K]

The standard form of the quadratic equation is ax^2 + bx + c. In vertex form, it's y = a(x – h)2 + k.
The graph of a quadratic equation is a parabola, which looks like a u. If <em>a</em> is negative then it's an upside down u.

6 0

3 years ago

Read 2 more answers

Determine the slope of the line that contains the given points.

nydimaria [60]

Answer:

slope = 2/3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

N-(-7)= 12 how do you rewrite

DiKsa [7]

Answer:

N + 7 = 12

Step-by-step explanation:

When you have a number minus a negative number, it's the same as addition.

4 0

3 years ago

Read 2 more answers

PLEASE HELP

NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base

H is the height of the pyramid

we have

$V=40\ units^{3}$

$H=6\ units$

substitute and solve for B

$40=\frac{1}{3}B(6)$

$120=B(6)$

$B=120/6=20\ units^{2}$

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

$V=BH$

we have

$B=20\ units^{2}$

$H=6\ units$

substitute

$V=(20)(6)=120\ units^{3}$

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

3 0

4 years ago