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Dennis_Churaev [7]

3 years ago

9

Ms. Chawla’s class has 35 students. On children’s day, she gave 2 chocolates to each child in her class. After that, 5 chocolate

s were left with her. How many chocolates did she have at the start?

2 answers:

Karolina [17]3 years ago

8 0

Answer:

75

Step-by-step explanation:

Total number of students = 35

Nø of chocolate received by each student = 2

Number of chocolates = 35 * 2 = 70

After the distribution of chocolate, remaining chocolates = 5

Then Now

Total chocolates = 70 + 5 = 75

Hope it will help :)

balandron [24]3 years ago

5 0

Answer:

75 Chocolates.

Step-by-step explanation:

She had 35 students and she gave each 2 chocolates. That's 70, but she had 5 left over. That makes the answer 75.

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L 5.2.3 Quiz: Two-Variable Systems: Substitution

Misha Larkins [42]

Answer:

We get x=3 and y=21

The ordered pair will be: (3,21)

Step-by-step explanation:

We need to use the substitution method to solve the system of equations.

$y = 10x-9\\y = x + 18$

For substitution method we substitute the value of x or y from one equation to other.

Let:

$y = 10x-9--eq(1)\\y = x + 18--eq(2)$

Putting value of y from equation 2 into equation 1

$y=10x-9\\Put\:y=x+18\\x+18=10x-9\\x-10x=-9-18\\-9x=-27\\x=\frac{-27}{-9}\\x=3$

So, we get value of x=3

Now, for finding value of y, We substitute the value of x

Find value of x from equation 2

$y=x+18\\x=y-18$

Now, putting value of x in equation 1

$y=10x-9\\Put\:x=y-18\\y=10(y-18)-9\\y=10y-180-9\\y-10y=-189\\-9y=-189\\y=\frac{-189}{-9}\\y=21$

So, we get value of y=21

So, We get x=3 and y=21

The ordered pair will be: (3,21)

6 0

3 years ago

Combine the like terms to make a simpler expression: 5n+6+(-7n)<br> plz hurry

azamat

-2n + 6 is the answer to this question

4 0

3 years ago

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The graph below represents the price of sending video messages using the services of a phone company. What is the constant of pr

musickatia [10]

taylor is wrong the answer is 24

3 0

3 years ago

Find the y intercepts of 3x^2+24x-51. quadratic formula

julia-pushkina [17]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, starting with the y-intercept. To find the y-intercept, set the x variable to zero and solve as such:

$y=3*0^2+24*0-51\\y=0+0-51\\y=-51$

<u>Your y-intercept is (0,-51).</u>

Next, using our equation plug the appropriate values into the quadratic formula:

$x=\frac{-24\pm \sqrt{24^2-4*3*(-54)}}{2*3}$

Next, solve the multiplications and exponent:

$x=\frac{-24\pm \sqrt{576-(-648)}}{6}\\\\x=\frac{-24\pm \sqrt{576+648}}{6}$

Next, solve the addition:

$x=\frac{-24\pm \sqrt{1224}}{6}$

Now, simplify the radical using the product rule of radicals as such:

Product Rule of Radicals: √ab = √a × √b

√1224 = √12 × √102 = √2 × √6 × √6 × √17 = 6 × √2 × √17 = 6√34

$x=\frac{-24\pm 6\sqrt{34}}{6}$

Next, divide:

$x=-4\pm \sqrt{34}$

<u>The exact values of your x-intercepts are (-4 + √34, 0) and (-4 - √34, 0).</u>

Now to find the approximate values, solve this twice: once with the + symbol and once with the - symbol:

$x=-4+ \sqrt{34},-4- \sqrt{34}\\x\approx 1.83, -9.83$

<u>The approximate values of your x-intercepts (rounded to the hundredths) are (1.83,0) and (-9.83,0).</u>

5 0

4 years ago

A news station would like to conduct an exit poll to determine the likelihood that a highly debated amendment will receive enoug

vladimir1956 [14]

Answer:

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

What expression would give the smallest sample size that will result in a margin of error of no more than 3 percentage points?

We have to find n for which M = 0.03.

We have no prior estimate for the proportion, so we use $\pi = 0.5$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.645*0.5$

$\sqrt{n} = \frac{1.645*0.5}{0.03}$

$(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2$

$n = (\frac{1.645*0.5}{0.03})^2$

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

3 0

3 years ago