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NeTakaya
3 years ago
13

Which system of equations represents the matrix shown below?

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

c

Step-by-step explanation:

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Help with this I don't know how to solve please!
WITCHER [35]

Answer:

sin∅ = 0.7311

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

sin∅ = opposite/hypotenuse

Step 1: Find our hypotenuse

14² + 15² = c²

c = √421

Step 2: Find sin∅

sin∅ = 15/√421

sin∅ = 0.731055

6 0
4 years ago
On a measure of artistic abilities the mean for college students in New Zealand is 150 and a standard deviation is 25 give the Z
Digiron [165]

The method for computing a z-score is  \bold{z = \frac{(x-\mu)}{\sigma}}, where x is the crude score, \bold{\mu} is the mean population, and \bold{\sigma} seems to be the <em><u>standard population difference.</u></em>

  • The Z value of x is a number \bold{\frac{(x - \text{mean(series))}}{\text{SD(series)}}} are defined where SD is the standard deviation.
  • Here, we consider series as scores of students of colleges in New Zealand for their artistic abilities.

\bold{\bar{x}=150}\\\\ \bold{\sigma=25}

following are the calculation of the Z scores:

\to \ (a)\  100:\  \text{Z score}=\frac{(100-150)}{25}= \frac{(-50)}{25} = -2\\\\\to \ (b)\  120:\  \text{Z score}=\frac{(120-150)}{25}= \frac{(-30)}{25} = -1.2\\\\\to \ (c)\  140:\  \text{Z score}=\frac{(140-150)}{25}= \frac{(-10)}{25} = -0.4\\\\\to \ (a)\  160:\  \text{Z score}=\frac{(160-150)}{25}= \frac{(10)}{25} = 0.4\\\\

Using formula:

\to \text{Raw score = Mean(series) +Z score} \times \text{SD(series)}

Calculating the Raw scores:

\text{(e) -1: Raw score= 150 +(-1)} \times 25 = 125 \\\\\text{(f) -0.8: Raw score= 150 +(-0.8)} \times 25 = 130\\\\\text{(e) -0.2: Raw score= 150 +(-0.2)} \times 25 = 145\\\\\text{(e) 1.38: Raw score= 150 +(1.38)} \times 25 = 184.5\\\\

Learn more:

brainly.com/question/12865701

3 0
3 years ago
Answer this please......
Brrunno [24]

Answer:

1). Option A

2). Option B

Step-by-step explanation:

Question 1

Rule for the dilation of a point by a scale factor 'k' is given by the rule,

(x, y) → (kx, ky)

By this rule image of point A when dilated by the scale factor = 1.25,

A(-12, -8) → A'[(-12 × 1.25), (-8 × 1.25)]

              → A'(-15, -10)

Option A will be the answer.

Question 2

Scale factor = \frac{\text{Dimension or one side of the image}}{\text{Dimension or one side of the preimage}}

From the figure attached,

Scale factor = \frac{F'E'}{FE}

                    = \frac{4}{14}

                    = \frac{2}{7}

Therefore, rule for the dilation of ABC to form image triangle A'B'C' will be,

(x, y) → (\frac{2}{7}x, \frac{2}{7}y)

Option B will be the answer.

8 0
3 years ago
Which of the expressions are equivalent to the one below? Check all that<br> apply
NeX [460]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
We choose a number from the set 1, 2, 3,..., 100 uniformly at random and denote this number by X. For each of the following choi
kiruha [24]

Answer:

(a) A and B are dependent.

(b) C and D are dependent.

(c) E and F are dependent.

Step-by-step explanation:

Two sets are said to be independent if the intersection of the two set is empty. That is the sets are disjoint.

Let's examine the situations to determine if they are independent or not.

(a) A = {2, 4, 6, . . . , 10, . . . , 20, . . .} and B = {5, 10, 15, . . . , 20, . . .}. Since A n B = {10, 20, . . .}, then the sets are dependent

(b) C = {10, 11, 12, . . . , 31, . . . , 62, . . . , 93, . . .} and D = {31, 62, 93}. Since C n D = {31, 62, 93}, then the sets are dependent.

(c) E = {5, 7, 11, . . .} and F = {5, 15, . . .}. Since E n F = {5}, then the set are dependent.

Thus

(a) A and B are dependent.

(b) C and D are dependent.

(c) E and F are dependent.

5 0
3 years ago
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