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Naddik [55]
3 years ago
9

Select all the solutions to the quadratic equation x2-4x-12=0

Mathematics
2 answers:
pav-90 [236]3 years ago
6 0
It can be factored.

We need two numbers that multiply to -12 and add to -4, so are two terms would be -6 and 2.

(x - 6) (x + 2) = 0

x = 6
x = -2
djverab [1.8K]3 years ago
5 0

Answer:

x1= -2

x2= 6

Step-by-step explanation:

x^2-4x-12=0

x^2+2x-6x-12=0

x(x+2)-6(x+2)

(x+2)*(x-6)

one solution

x+2=0

x=-2

other solution

x-6=0

x=6

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LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

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3 years ago
-2y + 6 = -12<br><br> Please help me what is Y
patriot [66]

Answer:

y = 9

Step-by-step explanation:

-2y + 6 = -12

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